This hash function is expressed as:
For each bit (Ci) in the hash code (1 ≤ i ≤ n):
Ci = bi1 ⊕ bi2 ⊕ g ⊕ bim
where:
Ci: ith bit of the hash codem: number of n-bit blocks in the inputbij: ith bit in jth block⊕: XOR operation
1. Initialize hash variable: Set hash to 0.
2. Iterate through each character in the input string:
• For each character in the input string:
• Get the ASCII code of the current character.
3. Perform XOR operation with the current character's ASCII code:
• Update the hash by performing XOR with the ASCII code of the current character.
4. Repeat for all characters:
• Continue this process for each character in the input string.
5. Convert the final hash value to a string:
• After processing all characters, convert the final hash value to a string.
6. Return the hashed value:
• The resulting string is the hashed value of the input.
Suppose we apply the provided hashing algorithm to the string "abc". The steps would be as follows:
1. The ASCII code for 'a' is 97.
* Initially, 'hash' is 0.
* Perform XOR operation: 'hash ^ 97' results in '97'.
* 'hash' is now updated to '97'.
2. The ASCII code for 'b' is 98.
* Perform XOR operation: '97 ^ 98' results in '3'.
* 'hash' is now updated to '3'.
3. The ASCII code for 'c' is 99.
* Perform XOR operation: '3 ^ 99' results in '96'.
* 'hash' is now updated to '96'.
In this way, if we hash the string "abc" using the algorithm, the resulting hashed value would be "96".